Question

Side of the red square is
1 side of the blue one is
4. Find the sides of all the
other squares.​

Answer 1

Answer:

ANSWER

Let the present age of Aftab's daughter =x years. and the present age of Aftab =y years, (y>x)

According to the given conditions, we have

Seven years ago,

(y−7)=7×(x−7)

⇒y−7=7x−49

⇒7x−y−42=0 ...(i)

Three years later,

(y+3)=3×(x+3)

⇒y+3=3x+9

⇒3x−y+6=0 ...(ii)

Thus, the algebraic relations are

7x−y−42=0,3x−y+6=0.

Now, we represent the problem graphically as below: 7x−y−42=0 ...(i)

3x−y+6=0 ...(ii)

From the graph, we find that

x=12

and y=42

Thus, the present age of Aftab's daugther =12 years and the present age of Aftab =42 years.

Answer 2

Is it a complete question?