Side of triangular field are 41 m 40 m and 9m find the area
Answers
Answered by
6
Hii friend,
Let A = 41 m , B = 40 m , C = 9m
Therefore,
S = 1/2 ( A+B+C)
= 1/2 ( 41+40+9) = 1/2 × 90 = 45 m
Therefore,
S-A = 45-41 = 4 m
S-B = 45-40 = 5 m
S-C = 45-9 = 36 m
Therefore,
Area of triangle = ✓ S(S-A)(S-B)(S-C)
= ✓45×4×5×36
= ✓32400 = 180 M².
HOPE IT WILL HELP YOU...... :-)
Let A = 41 m , B = 40 m , C = 9m
Therefore,
S = 1/2 ( A+B+C)
= 1/2 ( 41+40+9) = 1/2 × 90 = 45 m
Therefore,
S-A = 45-41 = 4 m
S-B = 45-40 = 5 m
S-C = 45-9 = 36 m
Therefore,
Area of triangle = ✓ S(S-A)(S-B)(S-C)
= ✓45×4×5×36
= ✓32400 = 180 M².
HOPE IT WILL HELP YOU...... :-)
Answered by
1
use the herons formula
a+b+c/2=s
area= under 4oots(s-a) (s-b)( s-c)
a+b+c/2=s
area= under 4oots(s-a) (s-b)( s-c)
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