sides AB and PQ of two similar triangle ABC and PQR are similar. if AB:PQ = 3:5 then triangle ABC: PQR is?
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if ∆ABC~∆PQR
then
ar∆ABC/ar∆PQR=(AB/PQ)^2 = (AC/DF)^2 =(BC/EF)^2
above is theorem in 10th class
you see your 10th class math book
ar∆ABC/ar∆PQR=(AB/PQ)^2=(3/5)^2
=9/25
then
ar∆ABC/ar∆PQR=(AB/PQ)^2 = (AC/DF)^2 =(BC/EF)^2
above is theorem in 10th class
you see your 10th class math book
ar∆ABC/ar∆PQR=(AB/PQ)^2=(3/5)^2
=9/25
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