Question

Sides of a cuboid is 8cm x 6 cm x 5 cm, then its total surface area is​

Answer 1

Given :

• Length (l) = 8 cm
• Breadth (b) = 6 cm
• Height (h) = 5 cm

To find :

• Total surface area of cuboid

According to the question :

→ Surface area of cuboid = 2(lb + bh + hl)

→ 2(8 × 6 + 6 × 5 + 5 × 8) cm²

→ 2( 48 + 30 + 40) cm²

→ 2 × 118 cm²

→ 236 cm²

So,the surface area is 236 cm²...

__________....

More formulas :

• Lateral surface area of cuboid = 2h (l + b)

• Volume of cuboid = l × b × h

• Volume of cube = (side)^3

• Lateral surface area of cube = 4 × (side)²

• Area of rectangle = l × b

• Area of square = side × side

Answer 2

$\huge\frak{Answer:-}$

Given:-

Dimensions of the Cuboid = $8 × 6 × 5 cm^3$

To Find: TSA of the Cuboid!

We know,

$\bf{T.S.A. \ of \ Cuboid = 2(lb + bh + lh)}$

Thus,

$= T.S.A. = 2(8 × 6 + 6 × 5 + 5 × 8) \ cm^2$

$= T.S.A. = 2(48 + 30 + 40) \ cm^2$

$= T.S.A. = 2(118) \ cm^2$

$= T.S.A. = 236 \ cm^2$

Thus, TSA of the cube is 236 cm².

$\frak{@Spammore’s \ Booster:-}$

• $TSA \ of \ Cube = 6l^2$,
• $LSA \ of \ Cube = 4l^2$,
• $Diagonal \ of \ Cube = l \sqrt{3}$,
• $LSA \ of Cuboid = 2h(l+b)$ &
• $Diagonal \ of \ Cuboid = \sqrt{{l}^{2}+{b}^{2}+{h}^{2}}$.

Refer to the extra knowledge given by @Blossomfairy above to know more! $\heartsuit$