Math, asked by shivkumarmaurya6778, 10 months ago

Sides of a nuclear power plant cooling tower form a hyperbola. the diameter of the bottom of the tower is 292 feet. the smallest diameter of the tower is 164 which is 408 feet above the ground.

the tower is 598 feet tall.​

Answers

Answered by jefferson7
5

Sides of a nuclear power plant cooling tower form a hyperbola. the diameter of the bottom of the tower is 292 feet. the smallest diameter of the tower is 164 which is 408 feet above the ground.

the tower is 598 feet tall.​

Step-by-step explanation:

Step one

x² / a²   - y² / b²  =  1                        ....(1)

The distance 2a is the smallest diameter

The diameter here is 164

2a = 164

a = 164/2

= 82

Substitute a = 82 in step one above

x² /(82)²   =  y²/b²

For y = -408( since it is above the ground) the value of x is :

x = ₊₋ 292/2

= 146

Substitute a = 82 y= -408 and x = ₊₋ 146

(₊₋146²  ) / (82)²   - (-408)²  / b²  = 1

21316 / 6724  - 166464/b²  = 1

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