Question

Sides of a right triangular field are 25cm, 24cm and 7 cm .

Answer 1

Step-by-step explanation:

Given right triangle

24+7+25 =56

s=56/2 =28

s×s-a×s-b×s-c

=28×4×21×3 the whole root.

=84cm square

Answer 2

The area of right triangular field is $84cm^{2}.$

Step-by-step explanation:

We have,

The sides of a right triangular field = 25cm, 24cm and 7 cm

Here,a = 25 cm, b = 24cm and c = 7 cm

To find, the area of right triangular field = ?

∴ $s=\dfrac{a+b+c}{2}$

$s=\dfrac{56}{2}=28cm$

We know that,

The area of a right triangular field $=\sqrt{s(s-a)(s-b)(s-c)}$

$=\sqrt{28(28-25)(28-24)(28-7)}$

$=\sqrt{28(3)(4)(21)}$

$=\sqrt{7\times 4\times 3 \times 4\times 7 \times 3}$

$=7\times 4\times 3cm^{2}$

$=84cm^{2}$

Hence, the area of right triangular field is $84cm^{2}.$