Question

Sides of a triangle are 10cm, 24cm and 26cm. Find its area and the altitude corresponding to the shortest side

Answer 1

Step-by-step explanation:

As the length of sides are a Pythagorean triplet,

10²+24²=26²

This is a right-angled triangle.

So,

The sides with 10cm and 24cm are the base and altitude, while the side with 26cm is the hypotenuse.

Area of triangle = 1/2 × 10×24

                          =120cm²

Also, its longest altitude is the 24cm side, since 10cm is shorter and the altitude from hypotenuse will also obviously be shorter.

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Answer 2

Answer:

a=10cm

b=24cm

c=26cm

s=a+b+c/2

s=10+24+26/2

s=30

area = √s(s-a) (s-b) (s-c)

= √30(30-10) (30-24) (30-26)

= √30×20×6×4

= √3*10*10*2*2*3*2*2

=it is forming a pair of each number so the one-one no. will get out from the pair and get separated from the route

=3*10*2*2

=120cm²

area is 120cm²

altitude is as follows:-

H²=P²+B²

H²=10²+26²

H²=100+676

H²=776

H =√776

H=27.85cm²

altitude=27.85cm²