SIDES OF A TRIANGLE ARE 11cm, 60cm AND 61cm. FIND THE ALTTITUDE OF THE SMALLES SIDE
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As we know that
the smallest altitude is present opposite to the longest side.
s=1/2(11+60+61)=1/2*132=66
area=66(66-11)(66-60)(66-61)
=66*55*6*5
=11*6*11*5*6*5=11*5*6=30*11=330sq.m
altitude=1/2*area=1/2*61*330=61*165=10065
the smallest altitude is present opposite to the longest side.
s=1/2(11+60+61)=1/2*132=66
area=66(66-11)(66-60)(66-61)
=66*55*6*5
=11*6*11*5*6*5=11*5*6=30*11=330sq.m
altitude=1/2*area=1/2*61*330=61*165=10065
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