Question

Sides of a triangle are 45 cm ,39 cm and 42cm. find its area
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Answer 1

Answer:

Area of Triangle = 756$cm^{2}$

Step-by-step explanation:

According to the information provided in the question it is given as

Sides of a triangle are 45 cm ,39 cm and 42 cm.

We need to find its area

The area of a triangle is total space occupied by the three sides of a triangle in a 2-dimensional plane.

Let us assume

a=45 ,b=39,c=42

S =a+b+c /2

S = 45+39+42 /2

S =126 /2

S = 63

Now applying the formula we get the answer

$\Delta^{2}=\mathrm{S}(\mathrm{S}-\mathrm{a})(\mathrm{S}-\mathrm{b})(\mathrm{S}-\mathrm{c})=63 \times 18 \times 24 \times 21$

$\Delta=\sqrt{63 \times 18 \times 24 \times 21}=756 \mathrm{~cm}^{2}$

Hence area of triangle is  756 $cm^{2}$