Question

Sides of a triangle are: 5k, -2k - 7l +3 and 6l - 8. Perimeter of this triangle is​

Answer 1

Perimeter of the rectangle = PQ + QR + RS + SP

                                       = b +l + b + l

                                       = 2b +2l

Again, 

ABCD is a rectangle. We know that the opposite sides of a rectangle are equal.



AB = CD = 5 cm and BC = AD = 3 cm

So, the perimeter of the rectangle ABCD = AB + BC + CD + AD = 5 cm + 3 cm + 5 cm + 3 cm = 16 cm

It can be written as 5 cm + 5 cm + 3 cm + 3 cm

                        = (2 × 5) cm + (2 × 3) cm

                        = 2 (5 + 3) cm

                        = 2 × 8 cm

                        = 16 cm

We add length and breadth twice to find the perimeter of a rectangle.

Perimeter of a rectangle = 2 (length + breadth)

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