Question

Sides of a triangle are in ratio of 12:17:25 and its perimeter is 540cm find its area

Answer 1

Answer:let the sides of the triangle be 12x,17x and 25x.

Perimeter of the triangle= 540cm

Hence,12x+17x+25x=540

54x=540

X=540/54

X=10

Hence sides of the triangle will be 12×10=120,17×10=170&25×10=250

Use heron's formula,

√s(s-a)(s-b)(s-c)

Where s is the semiperimeter

Semiperimeter=270cm

Area=√270(270-120)(270-170)(270-250)

√270(150×100×20)

√270×300000

√81000000

=9000sq.cm

Step-by-step explanation:

Answer 2

let the sides be 12x 17x 25x

perimeter = 12x + 17x + 25x

12x + 17x + 25x = 540

54x = 540

x = 540/54 = 10

the sides of triangle are

12 × 10 = 120

17 × 10 =170

25 × 10 = 250

Semiperemeter = 120 + 170 + 250/2

= 330

area = squareroot[330 (330-120) (330 -170)(330 - 250)]