Sides Of A Triangle Are In The Ratio 12 :17 : 25 and its perimeter is 540cm. Find its Area.
Answers
Answer:
9000cm^2 or 90 m^2
Step-by-step explanation:
given
sides are in the ratio 12 : 17 : 25
&
perimeter = 540
as we know that
perimeter of a triangle = (1st side + 2nd side + 3rd side)
=>
let
1st side be 12x
2nd............. 17x
3rd.............. 25x
now,
12x + 17x + 25x = 540
=> 54x = 540
=> x = 540/54
=> x = 10
so
1st side = 12x => 12×10 = 120cm
2nd side = 17x => 17×10 = 170cm
3rd side = 25x => 25×10 = 250cm
now
the area of the triangle = √s(s-a) (s-b) (s-c)
[ BY HERONS FORMULA]
where a, b, c are the three side and
s = semi perimeter => 1/2(a+b+c)
=> s = 1/2(120+170+250)
=> s = 1/2 × 540 = 270cm
now
area = √270(270-120) (270-170) (270-250)
=> area = √270(150×100×20)
=> area = √270 × 300000
=> area = √81000000
=> area = 9000 cm^2
or
area = 9000/100 = 90 m^2
Ratio of the sides of the triangle = 12 : 17 : 25
Let the common ratio be x then sides are 12x, 17x and 25x
Perimeter of the triangle = 540cm
12x + 17x + 25x = 540 cm
⇒ 54x = 540cm
⇒ x = 10
Sides of triangle are,
12x = 12 × 10 = 120cm
17x = 17 × 10 = 170cm
25x = 25 × 10 = 250cm
Semi perimeter of triangle(s) = 540/2 = 270cm
Using heron's formula,
Area of the triangle = √s (s-a) (s-b) (s-c)
= √270(270 - 120) (270 - 170) (270 - 250)cm2
= √270 × 150 × 100 × 20 cm2
= 9000 cm2.