Math, asked by ajithvillavadakara, 9 months ago

sides of a triangle are in the ratio 12:17:25 and its perimeter is1080m.find the cost of painting the triangle at the rate of rs.2 per 10 m square

Answers

Answered by merinmathew232
6

Answer:

Rs. 7200

Step-by-step explanation:

Let the sides be 12x, 17x,25x

Given Perimeter = 1080m

⇒12x + 17x + 25x = 1080m

⇒54x = 1080m

⇒x = 1080/54

⇒x = 20m

∴The sides are 12 X 20, 17 X 20, 25 X 20= 240, 340,500

Area of the triangle = \sqrt{s(s-a)(s-b)(s-c)}

s = \frac{a+b+c}{2}= \frac{240 + 340+ 500}{2} =\frac{1080}{2}= 540

∴Area =\sqrt{540(540-240)(540- 340) (540- 500)}

\sqrt{540 X 300 X 200 X 40}=36,000 m^{2}

Cost of painting = Rs. 2 x 36000/10= Rs. 7200

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