Question

sides of a triangle are in the ratio of 12:17:25 and it's perimeter is 540 cm find it's area ​

Answer 1

Answer:

9000 cm2

Step-by-step explanation:

Let the sides of the triangle be 12x, 17x and 25x

Perimeter of the triangle = 540 cm

∴ 12x + 17x + 25x = 540

⇒ 54x = 540 ⇒ x = 10

Let a = 12x = 12 x 10 = 120 cm

b = 17x = 17 x 10 = 170 cm

c = 25x = 25 x 10 = 250 cm

s = (a + b + c)/2 = (120 + 170 + 250)/2 = 540/2

= 270 cm

∴ Area of triangle = root under (√s(s -a) (s -b)(s -c))

= root under (√270(270 - 120)(270 - 170)(270 - 250))

= root under (√270 x 150 x 100 x 20)

= 100 under root(√27 x 15 x 20)

= 100 x 9 x 5 x 2

= 9000 cm2

Answer 2

Answer:

9000 cm^2

Step-by-step explanation:

Lets consider the x as the common multiple of the ratios.

So the sides would be 12x,17x and 25x.

Perimeter of a triangle=Sum of all sides.

540=12x+17x+25x.

540=54x

Therefore x is equal to 10

Sides 120,170,250

s= perimeter of a triangle/2

= 540/2

=270 cm

By Heron's Formula,

Area of a triangle= the whole root s(s-a)(s-b)(s-c)

= the whole root 270(270-120)(270-170)(270-250)

={the whole root 270*150*100*20} cm^2

√81000000 cm^2

=9000cm^2

hope this helps you..

(please mark my answer Brainliest)