sides of a triangle are in the ratio of 12:17:25 and it's perimeter is 540cm . find its area
Answers
Answered by
2
Answer:
⇒Let x be common ratio
∴ Sides of triangle will be: 12x,17x and 25x
⇒Perimeter =540 cm(given)
⇒12x+17x+25x=540 cm,
⇒54x=540 cm
⇒x=10 cm
∴ Sides of triangle: a=120,b=170,c=250 cms
⇒2S=540
⇒S=270 cm
A=
s(s−a)(s−b)(s−c)
=
270(270−120)(270−170)(270−250)
cm
2
=
270×150×100×20
cm
2
A=9000 cm
2
Answered by
16
Answer:
- Sides of a triangle are in the ratio of 12:17:25 and its perimeter is 540cm.
- Area of Triangle
- 12x
- 17x
- 25x
12x +17x + 25x = 540
54x =540
x = 10
Therefore the value x is 10
- 12x =12 *10 =120
- 17x =17 *10=170
- 25x= 25 * 10=250
The sides of the triangle are 120,170,250
S = a+b+c/2
120 +170 +250 /2
270
By using herons formula
√s( s-a) (s-b) (s-c)
√270(270-120) (2 70-170) (270-250)
√270*150*100*20
√81000000
9000cm
Therefore the area of the triangle is 9000 cm².
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