Math, asked by khandelwalshivam124, 11 months ago

sides of a triangle are in the ratio of 12:17:25 and its perimeter is 540 cm. Find its area.

Answers

Answered by pandiyanj
2

Answer:

9000cm^2

Step-by-step explanation:

ratio of sides

12: 17:25

let them be

12x,17x, 25x respectively

perimeter of a triangle = sum of all sides

540 = 12x,17x, 25x

540 = 54x

x = 10

all sides measure

12x = 12×10 = 120

17x = 17× 10 = 170

25x= 25 × 10 = 250

it's semiperimeter = 540/2

= 270

using heron's formula area of the triangle =

root {(s)(s-a)(s-b)(s-c)}

where s is the semiperimeter and a,b,c

area the sides of the triangle.

root {( 270)(270-120)(270-170)(270-250)}

= 9000cm^2.

Answered by rasrividya
0

Answer:

area of triangle is

9000cm^2

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