Math, asked by Shubham101010, 4 months ago

Sides of a triangle are in the ratio of 12:17: 25 and its perimeter is 540cm. Find its area. .

Answers

Answered by Anonymous
4

Answer:

SOLUTION

Ratio of the sides of the triangle = 12 : 17 : 25Let the common ratio be x then sides are 12x, 17x and 25xPerimeter of the triangle = 540cm12x + 17x + 25x = 540 cm⇒ 54x = 540cm⇒ x = 10Sides of triangle are,12x = 12 × 10 = 120cm17x = 17 × 10 = 170cm25x = 25 × 10 = 250cmSemi perimeter of triangle(s) = 540/2 = 270cmUsing heron's formula,Area of the triangle = √s (s-a) (s-b) (s-c)                                       = √270(270 - 120) (270 - 170) (270 - 250)cm2                                       = √270 × 150 × 100 × 20 cm2                                       = 9000 cm2

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Step-by-step explanation:

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Answered by santoshverma82
1

Step-by-step explanation:

let x be side of triangle

according to question-

first side=12x

second side=17x

third side=25x

perimeter =540

12x+17x+24x=540

54x=540

x=540/54x=10

then first side=12×10=120cm

second side=17×10=170 cm

third side=25×10=250

area of triangle=1/2×170×120

=10,200 cmxcm

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