Math, asked by sameekshasusatya123, 1 month ago


Sides of a triangle are in the ratio of 12:17:25 and its perimeter is 540cm. Find its area.​

Answers

Answered by s20161073
0

Answer:

Ratio of the sides of the triangle = 12 : 17 : 25Let the common ratio be x then sides are 12x, 17x and 25xPerimeter of the triangle = 540cm12x + 17x + 25x = 540 cm⇒ 54x = 540cm⇒ x = 10Sides of triangle are,12x = 12 × 10 = 120cm17x = 17 × 10 = 170cm25x = 25 × 10 = 250cmSemi perimeter of triangle(s) = 540/2 = 270cmUsing heron's formula,Area of the triangle = √s (s-a) (s-b) (s-c)                                       = √270(270 - 120) (270 - 170) (270 - 250)cm2                    

   = √270 × 150 × 100 × 20 cm2                                       = 9000 cm2

Answered by ranjunagar15
0

Answer:

9000 cm^2

We can solve it by Heron's Formula

Hope it is helpful

Thank You

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