sides of a triangle are in the ratio of 12:17:25 and its perimeter is 540 cm. Fimd its area
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Answered by
0
Hey
Here is your answer,
Let the sides of the triangle be 12x , 17x and 25x.
Given that,
Perimeter of the triangle = 540cm
12x + 17x + 25x = 540
54x = 540
X = 540/54
X = 10
12x = 12 x 10 = 120
17x = 17 x 10 = 170
25x = 25 x 10 = 250
Hope it helps you!
Here is your answer,
Let the sides of the triangle be 12x , 17x and 25x.
Given that,
Perimeter of the triangle = 540cm
12x + 17x + 25x = 540
54x = 540
X = 540/54
X = 10
12x = 12 x 10 = 120
17x = 17 x 10 = 170
25x = 25 x 10 = 250
Hope it helps you!
rumaburman07p6e3hu:
your half is correct
Answered by
2
Let the sides be 12a, 17a and 25a
Perimeter = 12a + 17a + 25a
=> 540 = 54a
=> a = 10
First side = 120 cm
Second side = 170 cm
Third side = 250 cm
s = 270 cm
Area = sqrt ( s (s-a) (s-b) (s-c)
= sqrt ( 270 × 20 × 100 × 150)
= 100 × sqrt ( 27 × 2 × 10 × 15)
= 100 × 3 × 3 × sqrt (2 ×10 ×5)
= 9000 cm^2
Perimeter = 12a + 17a + 25a
=> 540 = 54a
=> a = 10
First side = 120 cm
Second side = 170 cm
Third side = 250 cm
s = 270 cm
Area = sqrt ( s (s-a) (s-b) (s-c)
= sqrt ( 270 × 20 × 100 × 150)
= 100 × sqrt ( 27 × 2 × 10 × 15)
= 100 × 3 × 3 × sqrt (2 ×10 ×5)
= 9000 cm^2
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