Sides of a triangle are in the ratio of 12 : 17 : 25 and its perimeter is 540cm. Find its area.
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given the sides of the triangle in the ratio of 12 : 17 : 25
let the sides be 12x, 17x and 25x.
given the perimeter of the triangle = 540cm
therefore 12x + 17x + 25x = 540cm
>> 54x = 540cm
>> x = 540/54
>> x = 10
therefore the sides of the triangle are :-
◾12x = 12 × 10 = 120cm
◾17x = 17 × 10 = 170cm
◾25x = 25 × 10 = 250cm
semi-perimeter of the triangle = 540/2 = 270cm
let the sides of the triangle be a, b and c.
heron's formula = √s(s - a)(s - b)(s - c)
◾(s - a) = 270 - 120 = 150cm
◾(s - b) = 270 - 170 = 100cm
◾(s - c) = 270 - 250 = 20cm
therefore area of the triangle = √(270 × 150 × 100 × 20)
= √81000000
= 9000cm²
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