Math, asked by samzzzz0x, 6 months ago

SIDES OF A TRIANGLE ARE (x+3) CM , (x+5) CM AND (x+6) CM. ITS PERIMETER IS 28CM a. DETERMINE THE VALUE OF x

Answers

Answered by ankitpandey16648

0

Answer:

here giventhat sides are x+3, x+5, x+6

so now ,x+3+ x+5+x+6 =28

3x+14=28

3x=14

x=14/3

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