Question

Sides of 어 a triangle
in the a ratio
of 12:17:25 and ite perimeter 540cm.
find its
area.​

Answer 1

Answer:

hi,

HERE'S your answer

Step-by-step explanation:

Let the common ratio between the sides of the given triangle be- x

Therefore the side of triangle be -12x,17x,25x

Therefore the side of triangle be -12x,17x,25xPerimeter of this triangle-540cm

Therefore the side of triangle be -12x,17x,25xPerimeter of this triangle-540cm54x-540cm

Therefore the side of triangle be -12x,17x,25xPerimeter of this triangle-540cm54x-540cmX-10cm

Therefore the side of triangle be -12x,17x,25xPerimeter of this triangle-540cm54x-540cmX-10cmSides of triangle will be 120cm,170cm and 250cm

Side--Perimeter of triangle÷2

=540÷2=270 cm

area if triangle=√s(s-a)(s-b)(s-c)

=√270(270-120)(270-170)(270-250)

=√270*150*109*20

=9000 metre square

THEREFORE THE AREA OF TRIANGLE IS 9000 METRE SQUARE

HOPE IT HELPS!!

MARK AS BRAINLIEST!!

Answer 2

• The area of the triangle is 9000 cm sq.

Explanation:

Given:

The ratio of the sides if a triangle is 12:17:25

The perimeter of the triangle is 540 cm

To find:

The area of the triangle

So,

Let the sides of the triangle be

• a = 12x cm
• b = 17x cm
• c = 25x cm

According to question,

The perimeter of the triangle = 540

⇒ a + b + c = 540

⇒ 12x + 17x + 25x = 540

⇒ 54x = 540

⇒ x = 540 ÷ 54

[By transporting 54 to RHS]

⇒ x = 10

Thus,

The value of x is 10

Now the sides of the triangle are

• a = 12x = 12 * 10 = 120 cm
• b = 17x = 17 * 10 = 170 cm
• c = 25x = 25 * 10 = 250 cm

We can find the area of the triangle bye Heron's formula

S = semiperimeter = Periemter/2

S = 540/2 = 270

Now,

$=\sqrt{S(S-a)(S-b)(S-c)}$ units sq.

$=\sqrt{270(270-120)(270-170)(270-250)}$

$=\sqrt{270(150)(100)(20)}$

$=\sqrt{3*3*3*10*(3*5*10)(10*10)(2*10)}$

$=\sqrt{\underline{3*3}*\underline{3*3}*\underline{10*10}*\underline{10*10}*10*2*5}$

$=\sqrt{\underline{3*3}*\underline{3*3}*\underline{10*10}*\underline{10*10}*\underline{10*10} }$

= 3 * 3 * 10 * 10 * 10

= 9000 cm sq.