Question

sides of a triangles are in the ratio of 12:17:25 and its perimeter is 540cm. find its area?​

Answer 1

Step-by-step explanation:

9000 will be correct answer...

12x+17x+25x = 540

x = 10

therefore, sides =120,170,250

using heron's formula you can find it's area

s=270

a=170

b=120

c=250

then the correct answer will be 9000

Answer 2

Given:

Perimeter of triangle =540 cm

Ratio of its sides 12:17:25

⇒Let the common ratio of sides of triangle be x

therefore,

☆ Sides of triangle will be 12x,17x and 25x

●Perimeter means sum of all the sides.

⇒12x+17x+25x=540 cm

⇒54x=540 cm

⇒x=10 cm

So, Sides of triangle

a=12x=12×10⇒120 cm

b=17x=17×10 ⇒170 cm

c=25x=25×10⇒250cm

Now , we need to find semiperimeter of triangle to find its area by using the formula

$semiperimeter = \frac{540}{2}$

⇒Semiperimeter=270 cm

$area = \sqrt{s(s - a)(s - b)(s - c)}$

here s is used for semiperimeter

$area = \sqrt{270(270 - 120)(270 - 170)(270 - 250)}$

$= \sqrt{270 \times 100 \times 50 \times 20}$

$area = (9000) {cm}^{2}$