Question

Sides of a triangular field are 15 m, 16 m, 17 m. With the three corners of the field a cow, a
buffalo and a horse are tied separately with ropes of length 7 m each to graze in the field. Find
the area of the field which cannot be grazed by the 3 animals​

Answer 1

Answer:

Step-by-step explanation:

Answer

Given radius of each sector=7m

Now area of sector with ∠C=360∠C​×πr2=360∠c​×π(72)m2

Area of the sector with ∠B=360∠B​×πr2=360∠B​×π(72)m2

And area of the sector with ∠H=360∠H​×πr2=360∠H​×π(72)m2

Therefore sum of the areas =360∠C+∠B+∠H​×π×49=77m2

Semiperimeter=24 m

Therefore area of the triangular field =s(s−a)(s−b)(s−c)

​

=2421

​m2

So area which can not be grazed =(2421

​−77)m2