Sides of an equilateral triangle are 2x-3y+1, X+y-1 and 3x-y-9. Find its perimeter
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As all the sides of an equilateral triangle are equal, 2x−3y+1=x+y−1 and x+y−1=3x−y−9. Hence
x−4y=−2,........(1)
2x−2y=8...........(2)
Multiplying (2) by 2 and subtracting (1) from it, we get 3x=18. Hence x=6.
Finally 2y=2x−8=2(6)−8=12−8=4. Hence y=2.
Thus the side of the triangle is x+y−1=6+2−1=7cm. Its perimeter is 3×7=21 cm
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