Question

Sides of IstTriangle is 5 , 3 ,4 and inside is 18
And second ∆ sides is 3,5,4 and inside is 65
Then
If triangle side is 9,6,3 then inside is ?

Answer 1

[ Refer the attachment for figure. ]

Triangle (a) having sides 5, 3 and 4 and inside is 18.

Let it's first side be 5, second be 3 and 4 be third.

→ M = 5, J = 3 and N = 4

Now,

→ (J)² + (M + N)

→ (3)² + (5 + 4)

→ 9 + 9

→ 18 (which is correct)

Similarly, Triangle (b) having sides 3, 5 and 4 and inside is 65.

→ M = 3, J = 5 and N = 4

→ (J)² + (M + N)

→ (5)² + (3 + 4)

→ 25 + (7)

→ 32 (but correct one is 65)

So, the above formula is not applied on it.

Now,

For Triangle (a):

Sum the all sides + sum the middle one after splitting it.

→ 3 + 5 + 4 + (1 + 8) = 21

Now, for Triangle (b):

→ 3 + 5 + 4 + (6 + 5) = 23

Difference of two in both

For Triangle (c):

→ 9 + 6 + 3 + ( __ + __ ) = 25

→ 18 + ( __ + __ ) = 25

→ ( __ + __ ) = 25 - 18

→ ( 7 + 0 ) = 7

So,

→ 9 + 6 + 3 + (7 + 0) = 25

So, in triangle (c) sides are 9, 6, 3 and inside it 70 is present.

(Also, it can be 34, 43, 61, 16, 52, 25)

Answer 2

Given :-

→ 5 -- 3 -- 4 = 18

→ 3 -- 5 -- 4 = 65

→ 9 -- 6 -- 3 = ?

Solution :-

Adding All Digits we get :-

→ (5 + 3 + 4) + (1 + 8) = 21

Similarly,

→ ( 3 + 5 + 4) + (6 + 5) = 23 .

So, we can conclude That, 21 & 23 are In series with (+2) .

So, Our Next Outcome Sum will be = 23 + 2 = 25.

So,

→ ( 9 + 6 + 3) + (x + y) = 25

→ 18 + (x + y) = 25

→ (x + y) = 25 - 18

→ (x + y) = 7

So,

→ Possible Two - Digits Numbers are = { 70 , 16 , 61, 25, 52 , 34 & 43 }.

So, Now we Have to Check Options ,which one from These is given, That will be Our Answer.

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