Question

sides of the rhombus are 6cm long and one of the angle is 120°compute it's area
​

Answer 1

Answer:

we know area of rhombus ABCD= 2 area of triangle ABC

given AB = 6 CM and /_ABC = 120 degrees

so area of triangle ABC = 1/2 × AB × BC × sin120

=

$\frac{1}{2} \times 6 \times 6 \times \frac{ \sqrt{3} }{2} \\ = 9 \sqrt{3} \: {cm}^{2}$

so area of rhombus ABCD =

$18 \sqrt{3} {cm}^{2}$