Math, asked by mohdmzaidi1207, 7 months ago

sides of the right angle triangle
x cm , x+1 cm and x+ 3 cm
showe
x² -4x-8 =0 and solve the
equation to find the value of x​

Answers

Answered by avtarudra
0

Answer:

if there is any problem in understanding feel free to ask me,,,

Attachments:
Answered by DJBINOD007X
1

Step-by-step explanation:

Right angle triangle has the hypotanuse as the longest size.

So, we can assume x+3 to be hypotanuse.

According to Pythagorean Theorem,

Square of hypotanuse is just equal to the sum of the squares of height of triangle and it's base.

Therefore,

(x+3)^2=(x^2)+((x+1)^2)

x^2+6x+9=x^2+x^2+2x+1

x^2-4x-8=0 hence proved.

now, By SreedharAcharyan Method,

x= [-b +- root over( b^2 -4ac ) ]÷2a

where a=1 b= -4 and c= -8

because it is in the form of ax^2+bx+c=0

now after substitution of the values,

x= [4+- root over(16+32) ]÷ 2

x= 2+2root 3 centimetres

OR

x= 2-2root 3 centimetres

HOPE IT HELPS...

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