sides of the right angle triangle
x cm , x+1 cm and x+ 3 cm
showe
x² -4x-8 =0 and solve the
equation to find the value of x
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Step-by-step explanation:
Right angle triangle has the hypotanuse as the longest size.
So, we can assume x+3 to be hypotanuse.
According to Pythagorean Theorem,
Square of hypotanuse is just equal to the sum of the squares of height of triangle and it's base.
Therefore,
(x+3)^2=(x^2)+((x+1)^2)
x^2+6x+9=x^2+x^2+2x+1
x^2-4x-8=0 hence proved.
now, By SreedharAcharyan Method,
x= [-b +- root over( b^2 -4ac ) ]÷2a
where a=1 b= -4 and c= -8
because it is in the form of ax^2+bx+c=0
now after substitution of the values,
x= [4+- root over(16+32) ]÷ 2
x= 2+2root 3 centimetres
OR
x= 2-2root 3 centimetres
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