Question

sides of the triangle are 10 cm, 10 cm and 10cm.
find the area of the triangle?​

Answer 1

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• 25√3 cm² or 43.30cm² ( approximately)

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sides of triangle :-

• AB = 10 cm
• BC = 10 cm
• CD = 10 cm

that means triangle is a equilateral triangle

$\bold { \tt{ \underline{ \underline\color{blue}first \: method}}} :$

we know that:

$\bold{{ \tt \: area \: of \: equi \triangle = \frac{ \sqrt{3} }{4} {(side)}^{2} }}$

$\bold {{ \tt \implies \: \: ar( ABC) = \frac{ \sqrt{3} }{4} \times {(10)}^{2} }} \\ \\ \bold{{ \tt \implies \: \: ar(ABC) = \frac{ \sqrt{3} \times 100}{4} }} \\ \\ { \bold{ \tt \: \implies ar(ABC) = 25 \sqrt{3} }} \: \: \: \: \: \: \: \: \: \: \: \: \: \:$

so area of triangle ABC is 25√3 cm²

$\bold { \tt { \underline{ \underline\color{blue}second\: method}}} :$

area of triangle ABC by heron's formula

$\bold{a = \sqrt{s(s - a)(s - b)(s - c)} } \\ \\ \bold{s = \frac{a + b + c}{2} } \\ \\ \bold{a , b \: and \: c \: are \: sides \: of \: triangle}$

here,

$\bold{s = \frac{10 + 10 + 10}{2} } \\ \\ \bold{ \implies \: s = \frac{30}{2} = 15 }$

so area of ∆ABC,

$\bold{ \tt \: a = \sqrt{15(15 - 10)(15 - 10)(15 - 10)} } \\ \\ \bold{{ \tt \implies \:a = \sqrt{15 \times 5 \times 5 \times 5} }} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \bold{ \tt \implies \:a = 5 \times 5 \times \sqrt{3} } \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \bold{ \tt \: \implies \: a = 25 \sqrt{3} } \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:$

hence, area of triangle ABC is 25√3 cm²

Answer 2

Answer:

10.000

On Oct 2015. the Furniture purchased on 1st April 2014 was sold for 15.000 and on the

me dy a new Fuminute was purchased for 20.000

The fim charged depreciation at 10pa.om Reducing Balance Method.

Prepare Furniture Account and Depreciation Account for the year ending 31st March

2015. 2106 and 2017