Math, asked by lucifer5478, 7 months ago

sides of triangl6 are in ratio 3:5:7 and its perimeter is 300 cm.Find its area ​

Answers

Answered by okrishis
1

Answer:

ratio=3:5:7

let the numbers be=3x,5x,7x

3x+5x+7x=300

=15x=300

=x=300/15

=x=20cm

3x=60cm

5x=100cm

7x=140cm

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Answered by udaybhan2017chauhan
0

     \sqrt[1500]{3}{cm}^{2}

Answer:

GIVEN :-

Perimeter = 300cm

Sides in ratio = 3:5:7

FIND:-

Area = ?

__________________________

☢Step by Step☢

Perimeter of triangle = Sum of all sides

Let the sides be 3x,5x,7x

3x+5x+7x = 300cm

15x = 300cm

x =  \frac{300}{15} cm

= 20 cm

therefore, sides = 3x = 3×20=60cm

5x = 5×20=100cm

7x = 7×20=140cm

Sides = 60cm,100cm,140cm

NOW

By Heron's Formula-

Let a = 60cm, b = 100cm, c = 140cm

S =

 \frac{a + b + c}{2}  \\\\  =  \frac{60 + 100 + 140}{2} cm \\  =  \frac{300}{2}cm \\  = 150cm

Area =

 \sqrt{s(s - a)(s - b)(s - c)} sq.unit \\  =  \sqrt{150(150 - 60)(150 - 100)(150 - 140)}  \\  =  \sqrt{150 \times 90 \times 50 \times 10}  \\  =  \sqrt{2 \times 3 \times 5 \times 5 \times 2 \times 3 \times 3 \times 5 \times 2 \times 5\times 5 \times 2 \times 5}  \\  =   \sqrt[1500]{3}

Area of triangle =

     \sqrt[1500]{3}{cm}^{2}

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