Question

Sides of triangle are 2 cm , 3 cm ,and 5 cm , find the area of triangle ?​

Answer 1

Question ::-

Three sides of Triangle are 2 , 3 and 5 cm . Find the total area of triangle ?

Given ::-

• Sides of triangle = 2 cm , 3 cm , 5 cm .

To find ::-

• Area of triangle ?

Solution ::-

When side's of triangle are given we use Heron's formula.

Heron's formula

$= \: \sqrt{s(s - a)(s - b)(s - c)}$

Where ,

s = $\dfrac{a + b + c}{2}$

s = $\dfrac{2 + 3 + 5}{2}$

s = $\dfrac{10}{2}$

s = 5 cm

__________

$= \: \sqrt{s(s - a)(s - b)(s - c)}$

$= \: \sqrt{5(5 - 2)(5 - 3)(5 - 5)}$

$= \: \sqrt{5 \times 3 \times 2 \times 0}$

Area = 0

__________

In, s = $\dfrac{a + b + c}{2}$

• s = half perimeter of triangle.

• a = side of one side .

• b = side of second side .

• c = side of third side

Answer 2

$\huge\mathtt\red{ꪖꪀs᭙ᴇʀ}$

Given,

• Sides of the triangle are 2cm, 3cm and 5 cm.

To find out,

• Area of triangle.

Solution,

The lengths of the sides are

• a = 2 cm
• b = 3 cm
• c = 5 cm

$s = \frac{a + b + c}{2} = \frac{2 + 3 + 5}{2} = \frac{10}{2} = 5 \: cm$

We use the formula

$Δ= \sqrt{ s(s−a)(s−b)(s−c)}$

$Δ = \sqrt{5(5 - 2)(5 - 3)(5 - 5)}$

$Δ = \sqrt{(25 - 10)(25 - 15)(25 - 25)}$

$Δ = \sqrt{15 \times 10 \times 0}$

$Δ = 0$