Question

sides of triangle are 45cm, 39cm and 42cm.find area ​

Answer 1

Step-by-step explanation:

Answer

In △ABC, by Heron's formula we have

a=39cm,b=45cm and c=42cm

⇒s=

2

a+b+c

=

2

39+42+45

=63cm

∴ Area of ΔABC=

s(s−a)(s−b)(s−c)

=

63(63−39)(63−42)(63−45)

=

63×24×21×18

=756cm

2

Given both the triangle and parallelogram have equal areas.

A(□BCED)=base×height

⇒45×h=756cm

2

⇒h=16.8cm

Hope it helped you