Sides of triangle are 70 cm ,80cm,90cm find the area and length of the shortest altitude (use root 5=2.23
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Answer:
A= 70 cm
B= 80 cm
C= 90 cm
Semi-perimetre = (70+80+90)/2
= 240/2
= 120 cm
Area of ∆ = √{120(120-70)(120-80)(120-90)}
= √{120×50×40×30}
= √{4×3×10×5×10×3×10×4×10}
= 4×3×100√5
= 1200× 2.23
= 1200× 223/100
= 2676cm^2
Therefore, Area of ∆ is 2676cm^2
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