Question

sides of triangle are in the ratio 11:19:24cm and it's perimeter is 540cm. find its area.

Answer 1

perimeter of triangle = 540 cm

so 11x +19x +24x =540 cm

54x =540 cm

X =10 cm

11x = 110cm

19x = 190cm

24x = 240 cm

Answer 2

Area of triangle is $10182.33 cm^2$

Step-by-step explanation:

We are given that sides of triangle are in the ratio 11:19:24

Let the ratio be x

So, Sides of triangle are 11x , 19x and 24x

Perimeter of triangle = Sum of all sides

Perimeter of triangle = 11x+19x+24x=54x

It's perimeter is 540cm.

Sp. 54x = 540

x = 10 cm

So, Sides : 11x=11(10)=110 , 19x=19(10)=190 cm, 24x=24(10)=240 cm

$Area of triangle = \sqrt{s(s-a)(s-b)(s-c)}$

Where$s= \frac{a+b+c}{2}$

Substitute the values

$s=\frac{110+190+240}{2}=270$

$Area = \sqrt{270(270-110)(270-190)(270-240)}=10182.33 cm^2$

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