Sides of triangle are in the ratio of 12:17:25and its perimetre is 540 cm . Find its area solve
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Given
Sides of Triangle = 12, 17 , 25
Perimeter = 540.cm
12x + 17x + 25x = 540
54x= 540
X= 540 / 54
x = 10.cm
Sides
12.* 10 = 120
17*10.= 170
25*10 = 250
Semiperimeter = S / 2
Semiperimeter = 540./ 2
semiperimeter = 270
we use area formula
√s(s-a)(s-b) (s-c)
√270(270-120)(270-170)(270-250)
√270 *150 * 100* 20
answer = 9000cm²
Sides of Triangle = 12, 17 , 25
Perimeter = 540.cm
12x + 17x + 25x = 540
54x= 540
X= 540 / 54
x = 10.cm
Sides
12.* 10 = 120
17*10.= 170
25*10 = 250
Semiperimeter = S / 2
Semiperimeter = 540./ 2
semiperimeter = 270
we use area formula
√s(s-a)(s-b) (s-c)
√270(270-120)(270-170)(270-250)
√270 *150 * 100* 20
answer = 9000cm²
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