sides of triangular field are 15m 16m and 17m.with the three corners of the field a cow, a buffalo, and a horse are tied separately with ropes of length 7 m each to graze in the field.find area of the field which cannot be grazed by three animals
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first try to find out the angles of the triangle
area a sector of a circle is Area (Degrees) = πr^2 x θ/360
Area not grazed = area of the triangle - the three areas of sectors of the circle of radius 7 m
Heron's formula, using the lengths of the sides {a, b, c}:
s = (a + b + c) / 2 = <half the perimeter>
area = sqrt( s * (s - a) * (s - b) * (s - c) )
perimeter of the triangle = 15+16+17 =48
area of triangle = 109.98 sq. m
area of sectors = 25.489 + 28.40 + 23.077 =76.966
not grazed area = 109.980 - 76.966 = 33.014 sq. m
area a sector of a circle is Area (Degrees) = πr^2 x θ/360
Area not grazed = area of the triangle - the three areas of sectors of the circle of radius 7 m
Heron's formula, using the lengths of the sides {a, b, c}:
s = (a + b + c) / 2 = <half the perimeter>
area = sqrt( s * (s - a) * (s - b) * (s - c) )
perimeter of the triangle = 15+16+17 =48
area of triangle = 109.98 sq. m
area of sectors = 25.489 + 28.40 + 23.077 =76.966
not grazed area = 109.980 - 76.966 = 33.014 sq. m
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here is your correct answer
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