Math, asked by vivek209, 1 year ago

sides of triangular field are 15m 16m and 17m.with the three corners of the field a cow, a buffalo, and a horse are tied separately with ropes of length 7 m each to graze in the field.find area of the field which cannot be grazed by three animals

Answers

Answered by veon94
11
first try to find out the angles of the triangle

area a sector of a circle is Area (Degrees) = πr^2 x θ/360

Area not grazed = area of the triangle - the three areas of sectors of the circle of radius 7 m

Heron's formula, using the lengths of the sides {a, b, c}:
s = (a + b + c) / 2 = <half the perimeter>
area = sqrt( s * (s - a) * (s - b) * (s - c) )

perimeter of the triangle = 15+16+17 =48 

area of triangle = 109.98 sq. m

area of sectors = 25.489 + 28.40 + 23.077 =76.966

not grazed area = 109.980 - 76.966 = 33.014 sq. m

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Answered by sheela15
27
here is your correct answer
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