SIDES OF TWO SIMILAR TRIANGLES ARE IN THE RATIO 4 : 9, AREAS OF THESE TRIANGLES ARE IN THE RATIO ?
Answers
Answered by
3
Given :-
Sides of two similar triangles are in the ratio of 4:9
To Find :-
Ratio of their area
Solution :-
Area of ΔABC ∼ ΔPQR
ΔABC/ΔPQR = (side)²/side²
ΔABC/ΔPQR = (4)²/(9)²
ΔABC/ΔPQR = 16/81
Hence
The ratio is 16 : 81
Answered by
8
Answer:
- 16 : 81.
Step-by-step explanation:
Since, the ratio of the areas of two similar triangles is equal to the square of the ratio of their corresponding sides.
- ΔABC ~ΔDEF
⟹ ar(ΔABC)/ar(ΔDEF) = BC²/EF²
⇒ ar(ΔABC)/ar(ΔDEF) = 4²/9²
- 16/81
∴ Areas of these two triangles are in the ratio 16 : 81.
We also have,
⟹ ar(ΔABC)/ar(ΔDEF) = AB²/DE² = CA²/DF²
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