Sides other than the hypotenuse of a right triangle are length 16 cm and 8cmriangle
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let the ∆ be ABC
so, by pythagoras theorem,
let AC be the hypotenuse and AB and BC are two sides of a right angled ∆
Now,
AC^2=AB^2+BC^2
AC^2=16^2+8^2
AC^2=256+64
AC=√(320)
AC=17.88cm
=17.9cm
hope this helps u..........!!!!!!
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