Question

sides.
prone That in A ABC, sum of any Two
is Greater than the third side of the d.
i.e. [AB & Bes Ac​

Answer 1

$ANSWER</p><p></p><p>Construction: In ΔABC, extend AB to D in such a way that AD=AC.</p><p></p><p>In ΔDBC, as the angles opposite to equal sides are always equal, so,</p><p></p><p>∠ADC=∠ACD</p><p></p><p>Therefore,</p><p></p><p>∠BCD>∠BDC</p><p></p><p>As the sides opposite to the greater angle is longer, so,</p><p></p><p>BD>BC</p><p></p><p>AB+AD>BC</p><p></p><p>Since AD=AC, then,</p><p></p><p>AB+AC>BC</p><p></p><p>Hence, sum of two sides of a triangle is always greater than the third side.</p><p></p><p>$

this is your answer dear

Answer 2

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