Question

Sidhant solved 5 by 6 part of an exercise while Sarthak solved 10 by 11 of it. determine who solved the greater part of the exercise.
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Answer 1

Answer:

sarthak yes

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Answer 2

Sarthak solved the greater part of the exercise.

Step-by-step explanation:

According to the given information, Sidhant solved 5 by 6 part of an exercise. That means out of 6 parts of an exercise, Sidhant managed to solve 5 parts of it.

Thus, taken into fractional form, Sidhant solved $\frac{5}{6}$ th of the aforesaid exercise.

Again, according to the given information, Sarthak solved 10 by 11 part of an exercise. That means out of 11 parts of an exercise, Sarthak managed to solve 10 parts of it.

Thus, taken into fractional form, Sarthak solved $\frac{10}{11}$ th of the aforesaid exercise.

Now, comparing both fractions, we get,

Taking lcm of the denominators that is 6 and 11, we get, 66 as the least common multiple.

Then, we get,

For $\frac{5}{6} , \frac{10}{11}$,

Multiplying the first fraction by 11 on the numerator and the denominator and multiplying the second fraction on the numerator and the denominator, we get,

$\frac{55}{66} , \frac{60}{66}$

Since, 60 is greater than 55, Sarthak solved greater part of the exercise.

Thus, Sarthak solved the greater part of the exercise.

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