sif A (-3, 4), B (P.2), C(2,-1) are
collenear then find the value of P.
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If points are collinear, they are on a line.
So point B is on the line AC.
Graph of line AC : slope -1, passes C(2,-1)
∴
Put y value into function, and we get x.
Given point is B(P,2)
By putting x, y value
∴
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