Question

SiF4 oxidation number

Answer 1

Answer:

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Explanation:

SiF4 oxidation number

x -1 (4 ) = 0

x - 4 = 0

x = +4

Therefore oxidation number of Si in SiF4 is +4

Answer 2

Answer:

The Oxidation Number of Si in SiF4 is +4. The Oxidation number of SiF4 is 0.

Explanation:

• The Oxidation Number of an atom is the number of electrons loss or gained by that atom to form a bond.
• Oxidation number of a molecule is the sum of the oxidation number of the atoms present in the molecule.
• Oxidation number of a molecule is the sum of the oxidation number of the atoms present in the molecule.If the molecule is neutral, then its oxidation number is zero.
• Oxidation number of a molecule is the sum of the oxidation number of the atoms present in the molecule.If the molecule is neutral, then its oxidation number is zero.If the molecule is ionic, then its oxidation number is the number of positive or negative charge carried by the molecule.
• Oxidation number of a molecule is the sum of the oxidation number of the atoms present in the molecule.If the molecule is neutral, then its oxidation number is zero.If the molecule is ionic, then its oxidation number is the number of positive or negative charge carried by the molecule.Oxidation number is always mentioned by positive or negative sign .
• SiF4 is a neutral molecule.
• So the total oxidation number of Sif4 is Zero.
• In SiF4, oxidation number of Florine (F) is -1.
• Let the oxidation number of Si is x.
• So, Oxidation Number of Si + 4× Oxidation Number of F = 0 (4 is multiplied because four number of Florine atom is present.)
• x + 4×(-1)=0
• x-4=0
• x=+4
• So the Oxidation Number of Si is +4.
• The Oxidation Number of SiF4 is 0.