Question

sigma(2^i+3^i-1) where i =1,2,....18​

Answer 1

Step-by-step explanation:

=> Here, sigma(2^i +3^i -1)

= sigma(2^i +3^i -1)

= sigma(2+3-1)^i

= sigma(4)^i

For i=1 ,

= sigma(4)

For i=2 ,

= sigma(16)

For i=3 ,

= sigma(64)

For i=4 ,

= sigma(256)

.

.

=>simillarly ,

For i=18 ,

= sigma(68719476736)