Question

Sigma fixi minus mean is equal to

Answer 1

Answer:

Step-by-step explanation:

Let total no. of observation = n

and given mean of n observations = X

Then, (X₁+X₂+X₃+......+Xn)/n =X

⇒ X₁+X₂+X₃+.....+Xn= n×X

Now, Σ(Xi-X)={(X₁ -X)+(X₂ -X)+(X₃ -X)+....+(Xn -X) - n×X

      Σ(Xi - X)= (X₁+X₂+X₃+....+Xn) - n×x

      Σ(Xi - X)= n×X - n×X

∴Σ(Xi - X) = 0