Math, asked by sweetyadiza2323, 2 months ago

sigma(nx/n+1)^n
can you please give me the answer​

Answers

Answered by Anonymous
44

\large \sf \maltese  \:  \:  \:  { \underline{ \underline{Question \: : }}}

  • Evaluate the expression sig(nx/n+1)^n

Let's understand the concept,

  • As we know sig ( x ) is always 1 or 0 or -1. And is expressed as f( x ) = | x |/x [ it's written 0 only when x = 0 ] .
  • Now in this case we have to understand wether (nx/n+1)^n is negative or positive. Then only we can say the Answer.

let's do it!!

\large \sf \maltese  \:  \:  \:  { \underline{ \underline{Solution\: : }}}

 \bull \:  \:  \:  \:  \:  \:  \sf   sig {\bigg( \frac{nx}{n + 1}  \bigg)}^{n}

  • Now comes the two aspects of the problem. If n is an even number then (nx/n+1) will be a +ve number and in other hand if n is odd number then it's obvious that (nx/n+1) will be negative number.
  • Now, as x is belonging in the set of all real number so x can also be equal 0
  • So there are three solutions of this problem 1 & -1 & 0

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