sigma(nx/n+1)^n
can you please give me the answer
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- Evaluate the expression sig(nx/n+1)^n
Let's understand the concept,
- As we know sig ( x ) is always 1 or 0 or -1. And is expressed as f( x ) = | x |/x [ it's written 0 only when x = 0 ] .
- Now in this case we have to understand wether (nx/n+1)^n is negative or positive. Then only we can say the Answer.
let's do it!!
- Now comes the two aspects of the problem. If n is an even number then (nx/n+1) will be a +ve number and in other hand if n is odd number then it's obvious that (nx/n+1) will be negative number.
- Now, as x is belonging in the set of all real number so x can also be equal 0
- So there are three solutions of this problem 1 & -1 & 0
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