Question

Significance of food chain:-
I hope it will help you

Answer 1

Answer:

thanks for free points

Answer 2

Explanation:

$\sf {\dfrac {1}{x}}+\dfrac {1}{y}=4\dots\dots (1)$

$\sf \dfrac {2}{x}+\dfrac {4}{y}=8 \dots\dots (2)$

Let

$\qquad\quad {:}\longmapsto\sf \dfrac {1}{x}=u$

$\qquad\quad {:}\longmapsto\sf \dfrac {1}{y}=v$

Now the new equations

$\qquad\quad {:}\longmapsto\sf u+v=4\dots\dots (3)$

$\qquad\quad {:}\longmapsto\sf 2u-4v=8$

Make it simplified

$\qquad\quad {:}\longmapsto\sf \cancel {2} (u-2v)=\cancel {2} (4)$

$\qquad\quad {:}\longmapsto\sf u-2v=4\dots\dots (4)$

There are now Four ways by which we can solve

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$\qquad\quad {:}\longmapsto\sf Substitution\:method$

$\qquad\quad {:}\longmapsto\sf Elimination \:method$

$\qquad\quad {:}\longmapsto\sf Cross\:multiplication\:method$

$\qquad\quad {:}\longmapsto\sf Cramer 's\: rule$

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Let's use Elimination method

By multiplying eq (3) by 2 and eq (4) by 1 we get

$\qquad\quad {:}\longmapsto\sf 2u+2v=8\dots\dots(5)$

$\qquad\quad {:}\longmapsto\sf u-2v=4\dots\dots (6)$

Substract eq(6) from eq (5)

we get

$\qquad\quad {:}\longmapsto{\underline{\boxed{\sf u=4 }}}$

Substitute the value in eq (3)

$\qquad\quad {:}\longmapsto\sf u+v=4$

$\qquad\quad {:}\longmapsto\sf 4+v=4$

$\qquad\quad {:}\longmapsto\sf v=4-4$

$\qquad\quad {:}\longmapsto{\underline{\boxed{\sf v=0}}}$

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$\qquad\quad {:}\longmapsto\sf u={\dfrac {1}{x}} \\ \implies \sf \dfrac {1}{x}=4 \\ \implies x={\dfrac {1}{4}}$

$\qquad\quad {:}\longmapsto\sf v={\dfrac {1}{y}} \\ \implies\sf {\dfrac {1}{y}}=0 \\ \implies y=0$

$\therefore{\underline{\boxed{\sf (x,y)=({\dfrac {1}{4}}, 0)}}}$

$\Large\underbrace {Confused!!Let's\: verify}$

We have to put the values of x and y in the equation instead of x and y . If the answer comes zero then our solution is correct.

substitute the values in eq (1)

$\qquad\quad{:}\longrightarrow\sf \dfrac {1}{x}+{\dfrac {1}{y}}=4$

$\qquad\quad{:}\longrightarrow\sf \dfrac {1}{\dfrac {1}{4}}+{\dfrac {1}{0}}=4$

$\qquad\quad{:}\longrightarrow\sf 4+0=4$

$\qquad\quad{:}\longrightarrow\sf 4-4=0$

$\qquad\quad{:}\longrightarrow\sf 0=0$

$\therefore\underline{\sf Hence\:Verified}$