Question

Silicon carbide (SiC) is an important ceramic material.
It is produced by allowing silica (SiO:) to react with
carbon at high temperature as shown in the reaction:
SiO2 + 3C-SiC + 2CO
When 0.6kg sand is reacted with ercess of carbon, 0.2kg
of silicon carbide (SiC) is produced. What is the
percentage yield of silicon carbide (SIC)?
A) 35%
C) 50%
B) 40%
D) 45%​

Answer 1

Answer:

35% is the correct answer .

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Answer 2

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your answer with explanation:

Molar mass of SiC = 40 g/mol

Molar mass of SiO₂ (sand)  = 60 g/mol

When one mole of sand (60 g) reacts with 3 moles of carbon (36 g) gives one mole of Silicon carbide (40 g) and 2 moles of carbon monoxide (56g)

Now, 0.6 Kg = 600 g

600/60 = 10 moles of sand is present in 600 g of sand

Now, 10 moles of sand reacts only with 30 moles of carbon (mass of 30 moles of carbon is 360 g) to produce 10 moles of SiC and 20 moles of CO

In 0.2 Kg of SiC, there are: 200/40 = 5 moles

But, in this reaction, instead of 10 moles, only 5 moles are formed

And 5 moles of SiC weighs 200 g

10 moles of SiC weighs 400 g

Now, the percentage of yield

formula = $\frac{Actual\:\:yield}{Theoretical\:\:yield} \times 100$

The actual yield is: 200 g

The theoritical yield is 400 g

Now, your correct answer will be:

$\frac{200}{400} \times 100$ = 50%

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