Silicontetrachloride (SiCl4) can
be prepared by heating (Si) in chlorine gas (Cl2).
Si+2Cl2 =SiCl4
If we want to prepare to 10 moles
of (SiCl4) how many moles of
molecular chlorine (Cl2) will be used in
the reaction.
Answers
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Answer:
Si(s)+2Cl
2
(g)→SiCl
4
(l)
Two moles of chlorine is required for one mole of SiCl
4
.
So for 0.507 mole of SiCl
4
, 2×0.507=1.014 moles of chlorine is required.
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