Chemistry, asked by munazzairfan, 9 months ago

Silicontetrachloride (SiCl4) can
be prepared by heating (Si) in chlorine gas (Cl2).
Si+2Cl2 =SiCl4
If we want to prepare to 10 moles
of (SiCl4) how many moles of
molecular chlorine (Cl2) will be used in
the reaction.​

Answers

Answered by rishabhagarwal19
0

Answer:

Si(s)+2Cl

2

(g)→SiCl

4

(l)

Two moles of chlorine is required for one mole of SiCl

4

.

So for 0.507 mole of SiCl

4

, 2×0.507=1.014 moles of chlorine is required.

Similar questions