Question

Silver chloride dissolves in excess of
NH,OH. The cation present in solution is
Ag+
[Ag(NH3)4]+
[Ag(NH3)2]+
[Ag(NH3) 1*​

Answer 1

Silver chloride dissolves in excess of NH4OH. The cation present in solution is [Ag(NH3)2 ] +

AgCl + 2NH4OH ----> [Ag(NH3)2]C+2H2O

[Ag(NH3)2]Cl contains [Ag(NH3)2]+ and Cl- ions.

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Answer 2

Answer:

c

Explanation: