Question

Silver chloride is prepared by dissolving 0.5g of silver in nitric acid the mass of silver chloride obtain is 0.66g in another method 1g of silver metal is heated in a current of chlorine and the mass of siver chloride formed was 1.32g illustrate the law of constany combination by the above data

Answer 1

Given that ,

In First Case:-

0.5g silver produce = 0.66g. of silver chloride

1g silver produce = 0.66/0.5= 1.3g. of silver chloride.

1g silver produce= 1.3 g of silver chloride.

so

..

In 2nd Case:-.

1g silver produce = 1.3 g gram of silver chloride..

Hence in both cases mass of silver chloride remain same !...

or

.#second method mentioned in picture!!..

Thus it shows that law of constant proportion is true!!!!...